Question

test information description instructions from the list of choices, select the one best answer. multiple attempts not allowed. this test can only be taken once. force completion this test can be saved and resumed later. your answers are saved automatically. question completion status: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 moving to another question will save this response. question 23 of 25 question 23 4 points save answer suppose we have 2 identical bullets. one bullet is dropped from a height h while the other bullet is shot horizontally from the same height h. which bullet will strike the ground first? a. the horizontally shot bullet b. i dont know because i didnt watch the lecture video c. the dropped bullet d. both bullets will strike the ground at approximately the same time

Explanation:

Step1: Analyze vertical motion

The vertical - motion of both bullets is a free - fall motion. The initial vertical velocity of the dropped bullet is $v_{0y1}=0$, and the initial vertical velocity of the horizontally shot bullet is also $v_{0y2}=0$. The vertical displacement for both bullets is $y = h$, and the acceleration due to gravity is $g$. The equation for vertical displacement in free - fall is $y=v_{0y}t+\frac{1}{2}gt^{2}$. Since $v_{0y1} = v_{0y2}=0$, for the dropped bullet, $h=\frac{1}{2}gt_{1}^{2}$, so $t_{1}=\sqrt{\frac{2h}{g}}$. For the horizontally shot bullet, in the vertical direction, $h=\frac{1}{2}gt_{2}^{2}$, so $t_{2}=\sqrt{\frac{2h}{g}}$.

Step2: Compare the times

Since $t_{1}=\sqrt{\frac{2h}{g}}$ and $t_{2}=\sqrt{\frac{2h}{g}}$, we can see that $t_{1}=t_{2}$.

Answer:

d. both bullets will strike the ground at approximately the same time