QUESTION IMAGE
Question
translate 4 to the left and 6 up.
grid image
enter the coordinates of the new shape in the form (x, y):
r is at
c is at
d is at
e is at
To solve this, we first identify the original coordinates of points \( R \), \( C \), \( D \), and \( E \) from the graph. Let's assume:
- \( R \) is at \( (2, -8) \)
- \( C \) is at \( (1, -6) \)
- \( D \) is at \( (3, -4) \)
- \( E \) is at \( (5, -7) \)
A translation of 4 units left means we subtract 4 from the \( x \)-coordinate, and a translation of 6 units up means we add 6 to the \( y \)-coordinate. The translation rule is \( (x, y) \to (x - 4, y + 6) \).
For \( R' \):
- Original coordinates of \( R \): \( (2, -8) \)
- Apply the translation: \( x' = 2 - 4 = -2 \), \( y' = -8 + 6 = -2 \)
- So, \( R' \) is at \( (-2, -2) \)
For \( C' \):
- Original coordinates of \( C \): \( (1, -6) \)
- Apply the translation: \( x' = 1 - 4 = -3 \), \( y' = -6 + 6 = 0 \)
- So, \( C' \) is at \( (-3, 0) \)
For \( D' \):
- Original coordinates of \( D \): \( (3, -4) \)
- Apply the translation: \( x' = 3 - 4 = -1 \), \( y' = -4 + 6 = 2 \)
- So, \( D' \) is at \( (-1, 2) \)
For \( E' \):
- Original coordinates of \( E \): \( (5, -7) \)
- Apply the translation: \( x' = 5 - 4 = 1 \), \( y' = -7 + 6 = -1 \)
- So, \( E' \) is at \( (1, -1) \)
Final Answers:
- \( R' \) is at \( \boldsymbol{(-2, -2)} \)
- \( C' \) is at \( \boldsymbol{(-3, 0)} \)
- \( D' \) is at \( \boldsymbol{(-1, 2)} \)
- \( E' \) is at \( \boldsymbol{(1, -1)} \)
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To solve this, we first identify the original coordinates of points \( R \), \( C \), \( D \), and \( E \) from the graph. Let's assume:
- \( R \) is at \( (2, -8) \)
- \( C \) is at \( (1, -6) \)
- \( D \) is at \( (3, -4) \)
- \( E \) is at \( (5, -7) \)
A translation of 4 units left means we subtract 4 from the \( x \)-coordinate, and a translation of 6 units up means we add 6 to the \( y \)-coordinate. The translation rule is \( (x, y) \to (x - 4, y + 6) \).
For \( R' \):
- Original coordinates of \( R \): \( (2, -8) \)
- Apply the translation: \( x' = 2 - 4 = -2 \), \( y' = -8 + 6 = -2 \)
- So, \( R' \) is at \( (-2, -2) \)
For \( C' \):
- Original coordinates of \( C \): \( (1, -6) \)
- Apply the translation: \( x' = 1 - 4 = -3 \), \( y' = -6 + 6 = 0 \)
- So, \( C' \) is at \( (-3, 0) \)
For \( D' \):
- Original coordinates of \( D \): \( (3, -4) \)
- Apply the translation: \( x' = 3 - 4 = -1 \), \( y' = -4 + 6 = 2 \)
- So, \( D' \) is at \( (-1, 2) \)
For \( E' \):
- Original coordinates of \( E \): \( (5, -7) \)
- Apply the translation: \( x' = 5 - 4 = 1 \), \( y' = -7 + 6 = -1 \)
- So, \( E' \) is at \( (1, -1) \)
Final Answers:
- \( R' \) is at \( \boldsymbol{(-2, -2)} \)
- \( C' \) is at \( \boldsymbol{(-3, 0)} \)
- \( D' \) is at \( \boldsymbol{(-1, 2)} \)
- \( E' \) is at \( \boldsymbol{(1, -1)} \)