Question

trigonometric ratios in right triangles find sin(β) in the triangle.

Explanation:

Step1: Recall sine definition

In a right triangle, $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$.

Step2: Identify sides for $\beta$

For $\angle \beta$, opposite side is $AC = 15$, hypotenuse is $AB = 17$.

Step3: Calculate $\sin(\beta)$

$\sin(\beta) = \frac{AC}{AB} = \frac{15}{17}$.

Answer:

$\frac{15}{17}$