Question

two cars are traveling on a desert road between three consecutive poles, as shown in the figure. after 5.4 s, they are side by side at the next telephone pole. the distance between the poles is 65.4 m. find the displacement of car a after 5.4 s. answer in units of m. answer in units of m. part 2 of 4 find the displacement of car b after 5.4 s. answer in units of m. answer in units of m. part 3 of 4 find the average velocity of car a during 5.4 s. answer in units of m/s. answer in units of m/s.

Explanation:

Step1: Define displacement concept

Displacement is the change in position. Since both cars move from one pole to the next, displacement is the distance between poles.

Step2: Identify given distance

The distance between poles is $d = 65.4$ m.

Answer:

For part 1: 65.4 m
For part 2: 65.4 m
For part 3:

Step1: Recall average - velocity formula

The formula for average velocity is $v_{avg}=\frac{\Delta x}{\Delta t}$, where $\Delta x$ is displacement and $\Delta t$ is time.

Step2: Substitute values

$\Delta x = 65.4$ m and $\Delta t=5.4$ s. So, $v_{avg}=\frac{65.4}{5.4}\approx12.11$ m/s