Question

two identical cars, one on the moon and one on the earth, have the same speed and are rounding banked turns that have the same radius r. there are two forces acting on each car, its weight mg and the normal force fn exerted by the road. recall that the weight of an object on the moon is about one - sixth of its weight on earth. how does the centripetal force on the moon compare with that on earth? the centripetal force on the moon is less than that on the earth. the centripetal force on the moon is greater than that on the earth. the centripetal forces are the same. using multiple attempts will impact your score. 20% score reduction after attempt 3. etextbook and media save for later attempts: 1 of 5 used submit answer incorrect. how does the magnitude of the centripetal force depend upon the mass, speed, and radius of the turn? which of these variables (if any) are different on the moon compared to the earth?

Explanation:

Step1: Recall centripetal - force formula

The centripetal - force formula is $F_c=\frac{mv^{2}}{r}$, where $m$ is the mass of the object, $v$ is the speed, and $r$ is the radius of the circular path.

Step2: Analyze given conditions

The two cars are identical (same $m$), have the same speed $v$, and are on banked - turns with the same radius $r$. The weight of an object on the moon is about one - sixth of its weight on earth ($mg_{moon}=\frac{1}{6}mg_{earth}$), but the centripetal - force formula does not depend on the gravitational acceleration $g$.

Step3: Compare centripetal forces

Since $m$, $v$, and $r$ are the same for both cars (one on earth and one on the moon), using the formula $F_c = \frac{mv^{2}}{r}$, the centripetal forces are the same.

Answer:

The centripetal forces are the same.