Question

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subtracting $3x^2 + 4x - 5$ from $7x^2 + x + 9$ results in a polynomial. after subtracting $4x^2 - 3x$ from this polynomial, the difference is $square$.

Explanation:

Step1: Subtract first polynomial

$$(7x^2 + x + 9) - (3x^2 + 4x - 5)$$
$$=7x^2 + x + 9 - 3x^2 - 4x + 5$$
$$=(7x^2-3x^2)+(x-4x)+(9+5)$$
$$=4x^2 - 3x + 14$$

Step2: Subtract second polynomial

$$(4x^2 - 3x + 14) - (4x^2 - 3x)$$
$$=4x^2 - 3x + 14 - 4x^2 + 3x$$
$$=(4x^2-4x^2)+(-3x+3x)+14$$

Answer:

14