Question

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar.

$\triangle abc$ is an isosceles triangle with $\overline{ab} = \overline{bc} = 6$ units. $d$ and $e$ are the midpoints of $\overline{ab}$ and $\overline{bc}$, respectively.
the length of $\overline{ac}$ is 8 units. the length of $\overline{de}$ is \boxed{} units.

Explanation:

Step1: Recall Midsegment Theorem

The midsegment of a triangle is parallel to the third side and half its length.

Step2: Apply Theorem to $\overline{DE}$

Since $D,E$ are midpoints, $\overline{DE}$ is the midsegment for $\overline{AC}$.
$\overline{DE} = \frac{1}{2} \times \overline{AC}$
Substitute $\overline{AC}=8$:
$\overline{DE} = \frac{1}{2} \times 8$

Answer:

4