Question

uche pumps gasoline at a rate of $18\frac{\text{l}}{\text{min}}$. what is uches pumping rate in $\frac{\text{ml}}{\text{s}}$? \boxed{} $\frac{\text{ml}}{\text{s}}$

Explanation:

Step1: Convert liters to milliliters

We know that \( 1\space L = 1000\space mL \), so to convert \( 18\space \frac{L}{min} \) to \( \frac{mL}{min} \), we multiply by 1000.
\( 18\space \frac{L}{min} \times 1000\space \frac{mL}{L}= 18000\space \frac{mL}{min} \)

Step2: Convert minutes to seconds

We know that \( 1\space min = 60\space s \), so to convert \( \frac{mL}{min} \) to \( \frac{mL}{s} \), we divide by 60.
\( 18000\space \frac{mL}{min} \div 60\space \frac{s}{min}= \frac{18000}{60}\space \frac{mL}{s}= 300\space \frac{mL}{s} \)

Answer:

\( 300 \)