Question

use the aleks graphing calculator to find all the real zeros of the quadratic function.
$f(x)=-9x^{2}-24x-16$
round to the nearest hundredth.
if there is more than one answer, separate them with commas.
if there are no real zeros, click on
one\.
real zero(s):

Explanation:

Step1: Set function to 0

$-9x^2 -24x -16 = 0$

Step2: Use quadratic formula

For $ax^2+bx+c=0$, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$. Here $a=-9$, $b=-24$, $c=-16$.
First calculate discriminant:
$\Delta = (-24)^2 - 4(-9)(-16) = 576 - 576 = 0$

Step3: Solve for x

$x=\frac{-(-24)\pm\sqrt{0}}{2(-9)} = \frac{24}{-18} = -\frac{4}{3} \approx -1.33$

Answer:

-1.33