Question

use the distributive property to write an expression equivalent to $3(9p + 2r)$. $3(9p + 2r) = \boldsymbol{?} + \boldsymbol{?}$ (with options for the first? being 9p, 27p, 9, 27 and a dropdown for the second? not fully shown)

Explanation:

Step1: Apply distributive property

The distributive property states that \( a(b + c)=ab + ac \). For \( 3(9p + 2r) \), we multiply 3 with \( 9p \) and 3 with \( 2r \) separately.
First, calculate \( 3\times9p \): \( 3\times9p = 27p \)

Step2: Calculate the second term

Next, calculate \( 3\times2r \): \( 3\times2r=6r \)
So, \( 3(9p + 2r)=27p + 6r \) (assuming the second dropdown would have \( 6r \), but from the given first dropdown options, the first term is \( 27p \))

Answer:

First box: \( 27p \), second box (assuming the intended is \( 6r \), but based on the first dropdown options provided, the first term is \( 27p \))