Question

use the equation of motion to answer the question.

$x = x_0 + v_0t+\frac{1}{2}at^2$

an object has a starting position of x = 2 m, a starting velocity of 4.5 m/s, and no acceleration. which option shows the final position of the object after 2 s?
(1 point)
o 5.5 m
o 18 m
o 11 m
o 9 m

Explanation:

Step1: Identify given values

$x_0 = 2$ m, $v_0=4.5$ m/s, $a = 0$ m/s², $t = 2$ s

Step2: Substitute values into formula

$x=x_0 + v_0t+\frac{1}{2}at^{2}=2+4.5\times2+\frac{1}{2}\times0\times2^{2}$

Step3: Calculate the result

$x=2 + 9+0=11$ m

Answer:

11 m