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Question
use the equation $p = \frac{8.31}{v}$ where $p = $ pressure and $v = $ volume. what happens to the pressure as the volume approaches 0? explain your reasoning.
This is an inverse relationship: $p = \frac{8.31}{V}$ means pressure is inversely proportional to volume. As $V$ approaches 0 from the positive side (since volume cannot be negative), the denominator of the fraction becomes an extremely small positive number. Dividing a positive constant by an infinitesimally small positive value results in an infinitely large positive value.
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As the volume approaches 0, the pressure approaches positive infinity. This is because pressure and volume have an inverse relationship here, so a shrinking positive volume leads to an unbounded increase in pressure.