Question

use the following to answer #1 - 2.
$f(x)=\frac{1}{2}x - 1$
question 1
if $x = -8$, what must be the value of $f(x)$ in order to be part of the solution set?

Explanation:

Step1: Substitute $x=-6$ into function

$f(-6) = \frac{2}{3}(-6) - 1$

Step2: Calculate the first term

$\frac{2}{3}(-6) = -4$

Step3: Compute final value

$f(-6) = -4 - 1$

Answer:

$-5$