QUESTION IMAGE
Question
c. use the given information to complete the table. use 3.14 for π. then verify that π is the ratio of the circumference to the diameter for each circle. 1. circle 1: ( d = 4 , \text{cm} ) 2. circle 2: ( r = 7 , \text{mm} ) 3. circle 3: ( r = 12 , \text{in} ) 4. circle 4: ( d = 10 , \text{mm} ) 5. circle 5: ( r = 2.5 , \text{m} ) 6. circle 6: ( d = 7 , \text{in} )
| circle | circumference | radius | diameter | ( pi = \text{circumference} / \text{diameter} ) | |
| 1. | circle 1 | ||||
| 2. | circle 2 | ||||
| 3. | circle 3 | ||||
| 4. | circle 4 | ||||
| 5. | circle 5 | ||||
| 6. | circle 6 |
Step1: Recall circle formulas
Radius $r = \frac{d}{2}$, Diameter $d = 2r$, Circumference $C = \pi d = 2\pi r$, Ratio $\frac{C}{d} = \pi$
Step2: Solve for Circle 1
Given $d=4$ cm.
$r = \frac{4}{2} = 2$ cm
$C = 3.14 \times 4 = 12.56$ cm
$\frac{C}{d} = \frac{12.56}{4} = 3.14$
Step3: Solve for Circle 2
Given $r=7$ mm.
$d = 2 \times 7 = 14$ mm
$C = 2 \times 3.14 \times 7 = 43.96$ mm
$\frac{C}{d} = \frac{43.96}{14} = 3.14$
Step4: Solve for Circle 3
Given $r=12$ in.
$d = 2 \times 12 = 24$ in
$C = 2 \times 3.14 \times 12 = 75.36$ in
$\frac{C}{d} = \frac{75.36}{24} = 3.14$
Step5: Solve for Circle 4
Given $d=10$ mm.
$r = \frac{10}{2} = 5$ mm
$C = 3.14 \times 10 = 31.4$ mm
$\frac{C}{d} = \frac{31.4}{10} = 3.14$
Step6: Solve for Circle 5
Given $r=2.5$ m.
$d = 2 \times 2.5 = 5$ m
$C = 2 \times 3.14 \times 2.5 = 15.7$ m
$\frac{C}{d} = \frac{15.7}{5} = 3.14$
Step7: Solve for Circle 6
Given $d=7$ in.
$r = \frac{7}{2} = 3.5$ in
$C = 3.14 \times 7 = 21.98$ in
$\frac{C}{d} = \frac{21.98}{7} = 3.14$
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| Circle | Circumference | Radius | Diameter | $\pi =$ Circumference/ Diameter |
|---|---|---|---|---|
| 2. Circle 2 | 43.96 mm | 7 mm | 14 mm | 3.14 |
| 3. Circle 3 | 75.36 in | 12 in | 24 in | 3.14 |
| 4. Circle 4 | 31.4 mm | 5 mm | 10 mm | 3.14 |
| 5. Circle 5 | 15.7 m | 2.5 m | 5 m | 3.14 |
| 6. Circle 6 | 21.98 in | 3.5 in | 7 in | 3.14 |