Question

use the partial - quotients method to find 620÷19. fill in the missing numbers.
19)620
-190← ×19
-190← ×19
-190← ×19
-38← ×19

Explanation:

Step1: First partial - quotient

We know that \(19\times10 = 190\). To find how many times 19 goes into 620, we start with a reasonable estimate. \(620\div19\), we can see that \(19\times30=570\) and \(19\times 40 = 760\). Let's start with \(19\times10 = 190\). So the first partial - quotient is 10.

Step2: Second partial - quotient

After subtracting \(190\) from \(620\) (i.e., \(620 - 190=430\)), we can again subtract \(190\). Since \(430\div19\), and \(19\times10 = 190\), the second partial - quotient is also 10.

Step3: Third partial - quotient

After subtracting another \(190\) from \(430\) (i.e., \(430 - 190 = 240\)), we subtract \(190\) again. So the third partial - quotient is 10.

Step4: Fourth partial - quotient

After subtracting \(190\) from \(240\) (i.e., \(240-190 = 50\)), and since \(19\times2=38\), the fourth partial - quotient is 2.

Answer:

The partial - quotients are 10, 10, 10, 2. The long - division steps are:
\[

$$\begin{align*} &\text{Quotient: }10 + 10+10 + 2=32\\ &620\div19 = 32\cdots\cdots12 \end{align*}$$

\]
The missing numbers in order are 10, 10, 10, 2.