Question

use substitution to solve the system.
$x = 3y + 5$
$-5x + 4y = -14$
$x = \square$
$y = \square$

Explanation:

Step1: Substitute $x=3y+5$ into second equation

$-5(3y+5)+4y=-14$

Step2: Expand and simplify left side

$-15y-25+4y=-14$
$-11y-25=-14$

Step3: Isolate the $y$-term

$-11y=-14+25$
$-11y=11$

Step4: Solve for $y$

$y=\frac{11}{-11}=-1$

Step5: Substitute $y=-1$ into $x=3y+5$

$x=3(-1)+5$

Step6: Calculate the value of $x$

$x=-3+5=2$

Answer:

$x=2$
$y=-1$