Question

if v-t is a line increasing from 2 to 10 m/s in 4 s, acceleration is:
0 m/s^2
12 m/s^2
4 m/s^2
2 m/s^2

Explanation:

Step1: Recall acceleration formula

Acceleration \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v \) is change in velocity, \( \Delta t \) is time interval.

Step2: Calculate change in velocity

Initial velocity \( v_i = 2 \, \text{m/s} \), final velocity \( v_f = 10 \, \text{m/s} \). So \( \Delta v = v_f - v_i = 10 - 2 = 8 \, \text{m/s} \).

Step3: Calculate acceleration

Time \( \Delta t = 4 \, \text{s} \). Then \( a = \frac{8}{4} = 2 \, \text{m/s}^2 \).

Answer:

2 m/s² (the option with "2 m/s²")