Question

the vertices of $\triangle abc$ are $a(-6, -7)$, $b(-3, -10)$, and $c(-5, 2)$. find the vertices of $\triangle abc$, given the translation rule below.
$(x, y) \to (x + 11, y + 4)$

a $a(3, -3), b(8, -6), c(6, 6)$
b $a(5, -6), b(7, -6), c(6, 6)$
c $a(5, -3), b(8, -6), c(6, 6)$
d $a(6, -3), b(3, -6), c(6, 6)$

Explanation:

Step1: Translate point A

$A(-6,-7) \to (-6+11, -7+4) = (5, -3)$

Step2: Translate point B

$B(-3,-10) \to (-3+11, -10+4) = (8, -6)$

Step3: Translate point C

$C(-5,2) \to (-5+11, 2+4) = (6, 6)$

Answer:

c. $A'(5, -3), B'(8, -6), C'(6,6)$