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Question
the vertices for triangle abc are (2, 1), (3, 5) and (5, 3). the triangle will be rotated 90° counterclockwise about the origin. where will triangle abc be after being rotated?
Step1: Recall rotation rule
The rule for a 90 - degree counter - clockwise rotation about the origin is $(x,y)\to(-y,x)$.
Step2: Rotate point A
For point $A(2,1)$, using the rule $(x,y)\to(-y,x)$, we get $A'(-1,2)$.
Step3: Rotate point B
For point $B(3,5)$, using the rule $(x,y)\to(-y,x)$, we get $B'(-5,3)$.
Step4: Rotate point C
For point $C(5,3)$, using the rule $(x,y)\to(-y,x)$, we get $C'(-3,5)$.
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The vertices of $\triangle A'B'C'$ are $A'(-1,2)$, $B'(-5,3)$ and $C'(-3,5)$.