Question

we have $u$ terms on both sides of the equation, and we want to get the $u$ terms on one side. we can subtract $\frac{1}{2}u$ on the left side of the equation so that there are no $u$ terms on the left. then we need to subtract $\frac{1}{2}u$ from the right to keep the equation balanced. go for it.$\frac{1}{2}u + 2 = u + 6LXB0square = square$

Explanation:

Step1: Subtract $\frac{1}{2}u$ from left side

$\frac{1}{2}u + 2 - \frac{1}{2}u = 2$

Step2: Subtract $\frac{1}{2}u$ from right side

$u + 6 - \frac{1}{2}u = \frac{1}{2}u + 6$

Answer:

Top box: $2$
Bottom box: $\frac{1}{2}u + 6$