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Question
- we want to solve the following system of equations using the substitution method. equation 1 $5x - 3y = -15$ equation 2 $y = -4x - 5$ 7a first solve for $x$. enter your next step here
Step1: Substitute \( y \) in Equation 1
Since \( y = -4x - 5 \) (Equation 2), substitute \( y \) into Equation 1 (\( 5x - 3y = -15 \)).
\( 5x - 3(-4x - 5) = -15 \)
Step2: Simplify the equation
Distribute the -3: \( 5x + 12x + 15 = -15 \)
Combine like terms: \( 17x + 15 = -15 \)
Subtract 15 from both sides: \( 17x = -15 - 15 \)
\( 17x = -30 \)
Step3: Solve for \( x \)
Divide both sides by 17: \( x = \frac{-30}{17} \)
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\( x = -\frac{30}{17} \)