Question

what is the acceleration of a 32 kg object if a 6.75 n force is applied to it?
o 0.21 m/s²
o 4.74 m/s²
o 21.09 m/s²
o 216.00 m/s²

Explanation:

Step1: Recall Newton's second - law formula

$F = ma$, where $F$ is force, $m$ is mass, and $a$ is acceleration. We need to solve for $a$, so $a=\frac{F}{m}$.

Step2: Substitute given values

Given $F = 6.75\ N$ and $m = 32\ kg$. Then $a=\frac{6.75}{32}$.

Step3: Calculate the value of acceleration

$a=\frac{6.75}{32}= 0.2109375\ m/s^{2}\approx0.21\ m/s^{2}$

Answer:

A. $0.21\ m/s^{2}$