Question

what is the axis of symmetry for this quadratic function? f(x)=-2x^2 - 12x + 36 x = ?

Explanation:

Step1: Identify coefficients a and b

For \( f(x) = -2x^2 -12x + 36 \), \( a=-2 \), \( b=-12 \)

Step2: Apply axis of symmetry formula

\( x = -\frac{b}{2a} = -\frac{-12}{2(-2)} = \frac{12}{-4} = -3 \)

Answer:

\( x = -3 \)