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Question
what is the axis of symmetry for this quadratic function? f(x)=-4x^2 + 16x + 47 x = ? axis of symmetry: x = -\frac{b}{2a} simplify your answer completely.
Step1: Identify a and b
For \( f(x) = -4x^2 + 16x + 47 \), \( a=-4 \), \( b=16 \)
Step2: Apply axis formula
\( x = -\frac{b}{2a} = -\frac{16}{2\times(-4)} \)
Step3: Simplify calculation
\( x = -\frac{16}{-8} = 2 \)
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