Question

on \\(\sqrt{3q} = 6\\) for \\(q\\). what are the correct values for \\(a\\) and \\(b\\)? \\(a = 9\\) \\(b = 3\\) \\(a = 36\\) \\(b = 12\\) \\(a = 6\\) \\(b = 2\\)

Explanation:

Step1: Square both sides

$$(\sqrt{3q})^2 = 6^2$$
$$3q = 36$$

Step2: Solve for q

$$q = \frac{36}{3}$$
$$q = 12$$

For the values of A and B:

The solution $q=12$ corresponds to the option where $A=36$ (the result of squaring 6) and $B=12$ (the value of q).

Answer:

$q=12$
The correct values are: A = 36, B = 12