Question

what is the y - intercept of the function?
f(x) = - 0.5x² + 0.4x - 0.8
the y - intercept is
(type an ordered pair, using integers or decimals)

Explanation:

Step1: Recall y - intercept definition

The y - intercept of a function \(f(x)\) is the value of the function when \(x = 0\), and it is represented as the ordered pair \((0,f(0))\).

Step2: Substitute \(x = 0\) into \(f(x)\)

Given the function \(f(x)=- 0.5x^{2}+0.4x - 0.8\). When \(x = 0\), we substitute \(x\) into the function:
\(f(0)=-0.5(0)^{2}+0.4(0)-0.8\)
First, calculate \(-0.5(0)^{2}\): since any number multiplied by \(0\) is \(0\), \(-0.5\times0^{2}=0\).
Then, calculate \(0.4(0)\): \(0.4\times0 = 0\).
So, \(f(0)=0 + 0-0.8=-0.8\).

Answer:

\((0,-0.8)\)