Question

what are the x and y intercepts of f(x)=3x+12

Explanation:

Step1: Find x-intercept (set f(x)=0)

Set $f(x) = 0$, so $3x + 12 = 0$

Step2: Solve for x

Subtract 12, then divide by 3:
$3x = -12$
$x = \frac{-12}{3} = -4$

Step3: Find y-intercept (set x=0)

Set $x = 0$, so $f(0) = 3(0) + 12$

Step4: Calculate f(0)

$f(0) = 0 + 12 = 12$

Answer:

x-intercept: $(-4, 0)$; y-intercept: $(0, 12)$