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Question
what is the missing step in the proof? given: $overline{bc}paralleloverline{de}$, and $angle gaccongangle afd$ (figure). prove: $overleftrightarrow{gh}perpoverleftrightarrow{de}$ statement: $angle gac$ and $angle gab$ are supplementary. reason: linear pair theorem statement: $angle afecongangle afd$ reason: transitive property of equality statement: $angle gaccongangle baf$ reason: vertical angles theorem statement: $angle gac$ and $angle afd$ are supplementary. reason: linear pair theorem
| statement | reason |
|---|---|
| 2. $angle gaccongangle afe$ | for parallel lines cut by a transversal, corresponding angles are congruent. |
| 3. | |
| 4. $angle afd$ and $angle afe$ are supplementary. | linear pair theorem |
| 5. $mangle afd = mangle afe=90^{circ}$ | if two congruent angles are supplementary, then each angle is a right - angle. |
| 6. $overleftrightarrow{gh}perpoverleftrightarrow{de}$ | definition of perpendicular lines |
Step1: Analyze given and previous steps
We know $\angle GAC\cong\angle AFD$ (given) and $\angle GAC\cong\angle AFE$ (corresponding - angles for parallel lines). Also, we know $\angle AFD$ and $\angle AFE$ are supplementary from the linear - pair theorem later.
Step2: Determine the missing step
The missing step should be $\angle AFE\cong\angle AFD$ by the transitive property of equality since $\angle GAC\cong\angle AFD$ and $\angle GAC\cong\angle AFE$.
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Statement: $\angle AFE\cong\angle AFD$
Reason: Transitive Property of Equality