QUESTION IMAGE
Question
what do mountains breathe through?
do each exercise below. find your answer in the answer columns and notice the
letter next to it. look for this letter in the string of letters near the bottom of the page
and cross it out each time it appears. when you finish, write the remaining
letters in the rectangle at the bottom of the page.
① $9\frac{3}{4}$ ② $16\frac{2}{3}$ ③ $8\frac{8}{9}$ ④ $20\frac{13}{16}$ ⑤ $13\frac{5}{6}$
$\underline{-\\ 4\frac{1}{2}}$ $\underline{-\\ 7\frac{2}{5}}$ $\underline{-\\ 5\frac{1}{6}}$ $\underline{-\\ 3\frac{1}{4}}$ $\underline{-\\ 6\frac{1}{3}}$
⑥ $51\frac{4}{5}$ ⑦ $25\frac{7}{8}$ ⑧ $37\frac{7}{10}$ ⑨ $67\frac{4}{7}$ ⑩ $4\\ \frac{1}{5}$
$\underline{-\\ 8\frac{1}{2}}$ $\underline{-\\ 12\frac{5}{12}}$ $\underline{-\\ 28\frac{1}{6}}$ $\underline{-\\ 17}$ $\underline{-\\ 4\frac{3}{100}}$
⑪ $18\frac{3}{4}\\ -\\ 5\frac{1}{6}$ ⑫ $6\frac{2}{3}\\ -\\ 3\frac{4}{9}$ ⑬ $94\frac{11}{15}\\ -\\ 49\frac{2}{5}$
⑭ when arnold schwarzenegger was named mr. universe, he had a chest measurement of
$56\frac{7}{8}$ inches and a waist measurement of $32\frac{1}{4}$ inches. how much larger was his chest
than his waist?
⑮ the maximum weight for a basketball is $22\frac{9}{10}$ ounces. for a baseball it is $5\frac{1}{2}$ ounces,
and for a tennis ball it is $2\frac{1}{16}$ ounces. how much heavier is a maximum - weight basketball
than a maximum - weight baseball?
Step1: Convert to common denominators
Problem ①:
$9\frac{3}{4} - 4\frac{1}{2} = 9\frac{3}{4} - 4\frac{2}{4}$
Problem ②:
$16\frac{2}{3} - 7\frac{2}{5} = 16\frac{10}{15} - 7\frac{6}{15}$
Problem ③:
$8\frac{8}{9} - 5\frac{1}{6} = 8\frac{16}{18} - 5\frac{3}{18}$
Problem ④:
$20\frac{13}{16} - 3\frac{1}{4} = 20\frac{13}{16} - 3\frac{4}{16}$
Problem ⑤:
$13\frac{5}{6} - 6\frac{1}{3} = 13\frac{5}{6} - 6\frac{2}{6}$
Problem ⑥:
$51\frac{4}{5} - 8\frac{1}{2} = 51\frac{8}{10} - 8\frac{5}{10}$
Problem ⑦:
$25\frac{7}{8} - 12\frac{5}{12} = 25\frac{21}{24} - 12\frac{10}{24}$
Problem ⑧:
$37\frac{7}{10} - 28\frac{1}{6} = 37\frac{21}{30} - 28\frac{5}{30}$
Problem ⑨:
$67\frac{4}{7} - 17 = 67\frac{4}{7} - 17\frac{0}{7}$
Problem ⑩:
$4\frac{1}{5} - 4\frac{3}{10} = 4\frac{2}{10} - 4\frac{3}{10} = -\frac{1}{10}$
Problem ⑪:
$18\frac{3}{4} - 5\frac{1}{6} = 18\frac{9}{12} - 5\frac{2}{12}$
Problem ⑫:
$6\frac{2}{3} - 3\frac{4}{9} = 6\frac{6}{9} - 3\frac{4}{9}$
Problem ⑬:
$94\frac{11}{15} - 49\frac{2}{5} = 94\frac{11}{15} - 49\frac{6}{15}$
Problem ⑭:
$56\frac{7}{8} - 32\frac{1}{4} = 56\frac{7}{8} - 32\frac{2}{8}$
Problem ⑮:
$22\frac{9}{10} - 5\frac{1}{2} = 22\frac{9}{10} - 5\frac{5}{10}$
Step2: Subtract whole numbers & fractions
Problem ①:
$= (9-4) + (\frac{3}{4}-\frac{2}{4}) = 5 + \frac{1}{4} = 5\frac{1}{4}$
Problem ②:
$= (16-7) + (\frac{10}{15}-\frac{6}{15}) = 9 + \frac{4}{15} = 9\frac{4}{15}$
Problem ③:
$= (8-5) + (\frac{16}{18}-\frac{3}{18}) = 3 + \frac{13}{18} = 3\frac{13}{18}$
Problem ④:
$= (20-3) + (\frac{13}{16}-\frac{4}{16}) = 17 + \frac{9}{16} = 17\frac{9}{16}$
Problem ⑤:
$= (13-6) + (\frac{5}{6}-\frac{2}{6}) = 7 + \frac{3}{6} = 7\frac{1}{2}$
Problem ⑥:
$= (51-8) + (\frac{8}{10}-\frac{5}{10}) = 43 + \frac{3}{10} = 43\frac{3}{10}$
Problem ⑦:
$= (25-12) + (\frac{21}{24}-\frac{10}{24}) = 13 + \frac{11}{24} = 13\frac{11}{24}$
Problem ⑧:
$= (37-28) + (\frac{21}{30}-\frac{5}{30}) = 9 + \frac{16}{30} = 9\frac{8}{15}$
Problem ⑨:
$= (67-17) + \frac{4}{7} = 50 + \frac{4}{7} = 50\frac{4}{7}$
Problem ⑩:
$= -\frac{1}{10}$
Problem ⑪:
$= (18-5) + (\frac{9}{12}-\frac{2}{12}) = 13 + \frac{7}{12} = 13\frac{7}{12}$
Problem ⑫:
$= (6-3) + (\frac{6}{9}-\frac{4}{9}) = 3 + \frac{2}{9} = 3\frac{2}{9}$
Problem ⑬:
$= (94-49) + (\frac{11}{15}-\frac{6}{15}) = 45 + \frac{5}{15} = 45\frac{1}{3}$
Problem ⑭:
$= (56-32) + (\frac{7}{8}-\frac{2}{8}) = 24 + \frac{5}{8} = 24\frac{5}{8}$
Problem ⑮:
$= (22-5) + (\frac{9}{10}-\frac{5}{10}) = 17 + \frac{4}{10} = 17\frac{2}{5}$
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- $5\frac{1}{4}$
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