Question

1. what is the specific heat capacity of silver metal if 55.00 g of the metal absorbs 47.3j of heat and the temperature rises 15.0°c?

Explanation:

Step1: Recall the heat formula

The formula for heat absorbed is \( Q = mc\Delta T \), where \( Q \) is heat, \( m \) is mass, \( c \) is specific heat capacity, and \( \Delta T \) is temperature change. We need to solve for \( c \), so rearrange the formula: \( c=\frac{Q}{m\Delta T} \).

Step2: Substitute the given values

Given \( Q = 47.3\space J \), \( m = 55.00\space g \), \( \Delta T = 15.0^\circ C \). Substitute into the formula: \( c=\frac{47.3}{55.00\times15.0} \).

Step3: Calculate the value

First, calculate the denominator: \( 55.00\times15.0 = 825 \). Then, divide: \( c=\frac{47.3}{825}\approx0.0573\space J/(g\cdot^\circ C) \).

Answer:

The specific heat capacity of silver is approximately \( 0.0573\space J/(g\cdot^\circ C) \)