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what is the value of z, rounded to the nearest tenth? use the law of si…

Question

what is the value of z, rounded to the nearest tenth?
use the law of sines to find the answer.
○ 2.7 units
○ 3.2 units
○ 4.5 units
○ 5.3 units
law of sines: $\frac{sin(a)}{a} = \frac{sin(b)}{b} = \frac{sin(c)}{c}$

Explanation:

Step1: Find angle at X

The sum of angles in a triangle is $180^\circ$.
$\angle X = 180^\circ - 51^\circ - 76^\circ = 53^\circ$

Step2: Apply Law of Sines

Relate side $z$, side $XZ$, and their opposite angles.
$\frac{z}{\sin(76^\circ)} = \frac{2.6}{\sin(53^\circ)}$

Step3: Solve for z

Rearrange to isolate $z$ and calculate.
$z = \frac{2.6 \times \sin(76^\circ)}{\sin(53^\circ)}$
$\sin(76^\circ) \approx 0.9703$, $\sin(53^\circ) \approx 0.7986$
$z \approx \frac{2.6 \times 0.9703}{0.7986} \approx 3.2$

Answer:

3.2 units