Question

what is the value of $p$?
(there is a triangle $abc$ with a straight line passing through points $b$ and $a$. at point $b$, the angle between the left part of the straight line and side $bc$ is $136^circ$. we need to find the measure of angle $c$ (denoted as $p$).)
$p = \square^\circ$

Explanation:

Step1: Find angle at B

A straight line is \(180^\circ\), so the angle at \(B\) inside the triangle is \(180^\circ - 136^\circ = 44^\circ\).

Step2: Recognize isosceles triangle (or use linear pair for angle at A)

Since the triangle is isosceles (the two base angles are equal, as the base is on a straight line and the other two sides are equal in appearance, or we can find angle at \(A\) similarly: \(180^\circ - 136^\circ = 44^\circ\) too.

Step3: Sum of angles in a triangle

The sum of angles in a triangle is \(180^\circ\). So \(p = 180^\circ - 44^\circ - 44^\circ = 92^\circ\).

Answer:

\(92\)