Question

what is the volume of a sphere with a radius of 9.1 ft, rounded to the nearest tenth of a cubic foot?

Explanation:

Step1: Recall sphere volume formula

The formula for the volume $V$ of a sphere is $V = \frac{4}{3}\pi r^3$, where $r$ is the radius.

Step2: Substitute radius $r=9.1$ ft

$$V = \frac{4}{3}\pi (9.1)^3$$
First calculate $(9.1)^3 = 9.1 \times 9.1 \times 9.1 = 753.571$

Step3: Compute intermediate value

$$V = \frac{4}{3}\pi \times 753.571 \approx \frac{4}{3} \times 3.1416 \times 753.571$$
$\frac{4}{3} \times 3.1416 \approx 4.1888$, then $4.1888 \times 753.571 \approx 3156.6$

Answer:

$3156.6$ cubic feet