Question

what is $log_{5}(4 cdot 7)+log_{5}2$ written as a single log?$log_{5}21$$log_{5}26$$log_{5}30$$log_{5}56$

Explanation:

Step1: Simplify inside first log

$\log_5(4 \cdot 7) = \log_5 28$

Step2: Apply log product rule

$\log_5 28 + \log_5 2 = \log_5(28 \cdot 2)$

Step3: Calculate the product

$\log_5(28 \cdot 2) = \log_5 56$

Answer:

$\log_5 56$ (corresponding to the last option)