Question

what is the zero of $h(x)=2^x - 128$?
$x = $

Explanation:

Step1: Set h(x) equal to 0

$2^x - 128 = 0$

Step2: Isolate the exponential term

$2^x = 128$

Step3: Rewrite 128 as power of 2

$2^x = 2^7$

Step4: Equate exponents (same base)

$x = 7$

Answer:

$x=7$