Question

what are the zeros for the quadratic function $f(x)=x(x - 5)$?
a $x = 0, x = 5$
b $x = -5$
c $x = 5$
d $x = 0, x = -5$

Explanation:

Step1: Set function equal to 0

$f(x) = x(x-5) = 0$

Step2: Apply zero product rule

Set each factor to 0:
$x = 0$
$x - 5 = 0$

Step3: Solve for $x$

For $x - 5 = 0$, we get $x = 5$

Answer:

A. $x = 0, x = 5$