Question

where is the removable discontinuity of f(x) located?
○ x = -5
○ x = 0
○ x = -2
○ x = 5

Explanation:

Step1: Identify removable discontinuity

A removable discontinuity appears as a hole (open circle) on the graph, not an asymptote.

Step2: Locate the hole's x-value

The open circle is at $x=-2$ on the graph. The dashed line at $x=-4$ is a non-removable (infinite) discontinuity.

Answer:

C. $x = -2$