Question

which expression is equivalent to the given expression? assume the denominator does not equal zero.\\(\frac{14x^{2}y^{5}}{7x^{6}y^{1}}\\)\
a. \\(\frac{2y^{4}}{x^{4}}\\)\
b. \\(\frac{7y^{3}}{x^{4}}\\)\
c. \\(7x^{4}y^{4}\\)\
d. \\(2x^{2}y^{3}\\)

Explanation:

Step1: Simplify coefficient

$\frac{14}{7}=2$

Step2: Simplify $x$-terms

$x^{6-4}=x^2$

Step3: Simplify $y$-terms

$y^{7-4}=y^3$

Step4: Combine all simplified parts

$2 \times x^2 \times y^3$

Answer:

D. $2x^{2}y^{3}$