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Question
which method might be preferred if the coefficients of one variable are already opposites?
a. graphical
b. substitution
c. elimination
d. numerical
which system is best solved by the substitution method?
a. systems where one equation is easily solvable for one variable
b. systems with high coefficients
c. systems that involve quadratic equations
d. systems where both equations are in standard form
Step1: Match method to coefficient condition
When coefficients of one variable are opposites, adding the equations eliminates that variable directly, making elimination the ideal method.
Step2: Match system to substitution method
Substitution works best when you can easily isolate one variable in one equation and substitute it into the other equation, which describes the scenario in option a.
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- c. Elimination
- a. Systems where one equation is easily solvable for one variable