QUESTION IMAGE
Question
1 which is a solution to $-2x - 4 > 2$? a. $x = -4$ b. $x = -3$ c. $x = -1$ d. $x = 3$
Step1: Isolate the variable term
Add 4 to both sides:
$-2x - 4 + 4 > 2 + 4$
$-2x > 6$
Step2: Solve for x
Divide by -2 (reverse inequality):
$\frac{-2x}{-2} < \frac{6}{-2}$
$x < -3$
Step3: Check options
Find x less than -3:
- A. $x=-4$: $-4 < -3$ (valid)
- B. $x=-3$: $-3
less -3$ (invalid)
- C. $x=-1$: $-1
less -3$ (invalid)
- D. $x=3$: $3
less -3$ (invalid)
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A. $x = -4$