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Question
which statement best describes how to determine whether $f(x) = x^2 - x + 8$ is an even function?
determine whether $(-x)^2 - (-x) + 8$ is equivalent to $-(x^2 - x + 8)$.
determine whether $(-x)^2 - (-x) + 8$ is equivalent to $x^2 - x + 8$.
determine whether $-x^2 - (-x) + 8$ is equivalent to $-(x^2 - x + 8)$.
determine whether $-x^2 - (-x) + 8$ is equivalent to $x^2 - x + 8$.
To determine if a function \( f(x) \) is even, we use the definition of an even function: \( f(-x) = f(x) \).
Step 1: Recall the definition of an even function
A function \( f(x) \) is even if for all \( x \) in the domain, \( f(-x) = f(x) \). So we need to find \( f(-x) \) and check if it equals \( f(x) \).
Step 2: Find \( f(-x) \) for \( f(x) = x^2 - x + 8 \)
Substitute \( -x \) into the function:
\( f(-x) = (-x)^2 - (-x) + 8 \)
Step 3: Check the condition for an even function
We need to determine if \( f(-x) \) (which is \( (-x)^2 - (-x) + 8 \)) is equivalent to \( f(x) \) (which is \( x^2 - x + 8 \)).
Now let's analyze the options:
- Option 1: Checks if \( f(-x) = -f(x) \), which is for odd functions, not even.
- Option 2: Checks if \( f(-x) = f(x) \), which is the definition of an even function.
- Option 3: Incorrectly computes \( f(-x) \) (wrong sign on \( x^2 \)) and checks against \( -f(x) \), not relevant.
- Option 4: Incorrectly computes \( f(-x) \) (wrong sign on \( x^2 \)) and checks against \( f(x) \), but the computation of \( f(-x) \) is wrong.
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The correct option is the second one: "Determine whether \((-x)^2 - (-x) + 8\) is equivalent to \(x^2 - x + 8\)."