Question

$=\frac{(2)(1)(-4)}{(1)(6)(5)}$
$=\frac{-8}{30}$
$=-\frac{4}{15}$

$=\frac{(2)(1)(-4)}{(1)(6)(-5)}$
$=\frac{-8}{-30}$
$=\frac{4}{15}$

whose solution is correct and why?
○ nico is correct because he knew that $-\frac{4}{5}=\frac{-4}{-5}$.
○ nico is correct because he knew that $-\frac{4}{5}=\frac{-4}{5}$.
○ lorena is correct because she knew that $-\frac{4}{5}=\frac{-4}{5}$
○ lorena is correct because she knew that $-\frac{4}{5}=\frac{-4}{-5}$

Explanation:

Step1: Evaluate Nico's calculation

$$\frac{(2)(1)(-4)}{(1)(6)(5)} = \frac{-8}{30} = -\frac{4}{15}$$

Step2: Evaluate Lorena's calculation

$$\frac{(2)(1)(-4)}{(1)(6)(-5)} = \frac{-8}{-30} = \frac{4}{15}$$

Step3: Verify sign equivalence

$$-\frac{4}{15} = \frac{-4}{15}$$

Answer:

Nico is correct because he knew that $-\frac{4}{15} = \frac{-4}{15}$.