Question

write the logarithmic equation as an exponential equation. $log_{2}left(\frac{1}{64}
ight)=-6$

Explanation:

Step1: Recall log-exponential conversion rule

For $\log_b(x) = y$, $b^y = x$

Step2: Substitute values into rule

Here $b=2$, $y=-6$, $x=\frac{1}{64}$

Answer:

$2^{-6} = \frac{1}{64}$