Question

write a recursive formula for the following arithmetic sequence
-26, -20, -14, -8, ...
(a_1 = square)
(a_n = square) for (n geq 2)

Explanation:

Step1: Identify first term

The first term of the sequence is $a_1 = -26$.

Step2: Calculate common difference

Find the difference between consecutive terms: $-20 - (-26) = 6$.

Step3: Write recursive formula

For arithmetic sequences, $a_n = a_{n-1} + d$ where $d=6$ and $n\geq2$.

Answer:

$a_1 = -26$
$a_n = a_{n-1} + 6$ for $n \geq 2$