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Question
write a two - column proof. given: ℓ∥m, ∠1≅∠2 prove: a∥b geometry chapter 3 resource book
Step1: Identify corresponding - angles
Since $\ell\parallel m$, $\angle1$ and $\angle3$ are corresponding angles, so $\angle1\cong\angle3$ (Corresponding - Angles Postulate).
Step2: Identify vertical - angles
$\angle2$ and $\angle3$ are vertical angles, so $\angle2\cong\angle3$ (Vertical Angles Theorem).
Step3: Use the Transitive Property
Since $\angle1\cong\angle3$ and $\angle2\cong\angle3$, by the Transitive Property of Congruence, $\angle1\cong\angle2$. Then, since $\angle1$ and $\angle2$ are corresponding angles formed by lines $a$ and $b$ with a transversal, $a\parallel b$ (Converse of the Corresponding - Angles Postulate).
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The two - column proof is as follows:
| Statements | Reasons |
|---|---|
| 2. $\angle1\cong\angle3$ | Corresponding - Angles Postulate |
| 3. $\angle2\cong\angle3$ | Vertical Angles Theorem |
| 4. $\angle1\cong\angle2$ | Transitive Property of Congruence |
| 5. $a\parallel b$ | Converse of the Corresponding - Angles Postulate |