Question

1-4 exit ticket
answer each of the following.
(a) use the distributive property to write the product below in standard form.
$2x^2y(5x^2 - 7xy^4)$
(b) fill in the blank below to make the equation an identity.
$20y^2 + 15y = 5y(\underline{\quad\quad})$

Explanation:

Step1: Distribute $2x^2y$ to each term

$2x^2y \cdot 5x^2 - 2x^2y \cdot 7xy^4$

Step2: Calculate each product

$10x^{2+2}y - 14x^{2+1}y^{1+4} = 10x^4y - 14x^3y^5$

Step3: Factor out $5y$ from left side

$\frac{20y^2}{5y} + \frac{15y}{5y} = 4y + 3$

Answer:

(a) $\boldsymbol{10x^4y - 14x^3y^5}$
(b) $\boldsymbol{4y + 3}$