QUESTION IMAGE
Question
10 instrucciones: une cada gráfica con su pendiente correcta.
Step1: Identify two points on the line
From the first graph, we can see two points: \((-2, 2)\) and \((2, 1)\).
Step2: Use the slope formula
The slope formula is \(m=\frac{y_2 - y_1}{x_2 - x_1}\). Let \((x_1,y_1)=(-2,2)\) and \((x_2,y_2)=(2,1)\). Then \(m = \frac{1 - 2}{2 - (-2)}=\frac{-1}{4}=-\frac{1}{4}\).
For the second graph (the lower one), let's assume a point (though not fully visible, but from the trend). Wait, maybe the first line's slope is calculated as above. Let's re - check the first line:
Points are \((-2,2)\) and \((2,1)\). So \(x_1=-2,y_1 = 2,x_2=2,y_2=1\).
\(m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{1 - 2}{2-(-2)}=\frac{-1}{4}=-\frac{1}{4}\)
The second line (lower one) seems to have a positive slope. Let's say we have a point like \((2,1)\) (assuming, but maybe the key is to calculate the slope of the first line as above. Since the problem is to line each graph with its correct slope, we first calculate the slope of the first line.
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The slope of the first line (with points \((-2,2)\) and \((2,1)\)) is \(-\frac{1}{4}\). For the second line, if we assume a point (e.g., if it has points like \((2,1)\) and \((4,2)\), slope would be \(\frac{2 - 1}{4 - 2}=\frac{1}{2}\), but based on the first line calculation, the slope is \(-\frac{1}{4}\).