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2.10 quiz: factor quadratic trinomials due: fri feb 6, 2026 11:59pm att…

Question

2.10 quiz: factor quadratic trinomials
due: fri feb 6, 2026 11:59pm
attempt 1
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next up: submit assignment
available until mar 20, 2026 11:59pm
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factor completely.
(a^2 + 3a - 28)
enter your answer in the box.

Explanation:

Step1: Identify target factor pair

Find two numbers that multiply to $-28$ and add to $3$. The numbers are $7$ and $-4$, since $7 \times (-4) = -28$ and $7 + (-4) = 3$.

Step2: Write factored form

Express the trinomial as a product of two binomials using the found pair.
$a^2 + 3a - 28 = (a + 7)(a - 4)$

Answer:

$(a + 7)(a - 4)$