Question

1. when light strikes the gate of the device shown below

a. +v_cc drops to zero.
b. r_l opens.
c. v_cc is dropped across r_l.
d. 0 v is dropped across r_l.

Explanation:

Step1: Analyze photodiode behavior

When light strikes the photodiode (the device in the circuit), it conducts.

Step2: Consider circuit operation

When the photodiode conducts, it is like a closed - switch. So the voltage $V_{CC}$ will be dropped across the load resistor $R_{L}$.

Answer:

C. $V_{CC}$ is dropped across $R_{L}$.