Question

1. simplify the expression.

\log_{7}7^{-3x}=\square

Explanation:

Step1: Apply logarithm power rule

$\log_{7}7^{-3x} = -3x \cdot \log_{7}7$

Step2: Use $\log_b b = 1$

$-3x \cdot 1 = -3x$

Answer:

$-3x$